(x^2+8)=(x-3)

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Solution for (x^2+8)=(x-3) equation: 



(x^2+8)=(x-3)

We move all terms to the left:

(x^2+8)-((x-3))=0

We get rid of parentheses

x^2-((x-3))+8=0



We calculate terms in parentheses: -((x-3)), so:

(x-3)

We get rid of parentheses

x-3

Back to the equation:

-(x-3)



We get rid of parentheses

x^2-x+3+8=0

We add all the numbers together, and all the variables

x^2-1x+11=0

a = 1; b = -1; c = +11;
Δ = b2-4ac
Δ = -12-4·1·11
Δ = -43
Delta is less than zero, so there is no solution for the equation

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